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You can pass the parameter i.e. command line option to function as you passed to shell script. As you know you can define the function as follows:

function function-name( )
[
     statement1
     statement2
     statementN
]

And you can call this function (without command line option) within the shell script as follows:

function-name

You can pass the parameter to function i.e. command line option to function as follows:

function-name arg1 arg2 arg3 argN

To clear you idea lets write shell script:

$ vi pass
function demo()
[
echo "All Arguments to function demo(): $*"
echo "First argument $1"
echo "Second argument $2"
echo "Third argument $3"
return
]
#
# Call the function
#
demo -f foo bar

Run the above shell script as follows:
$ chmod +x pass
$ ./pass

All Arguments to function demo(): -f foo bar
First argument -f
Second argument foo
Third argument bar

As you can see the demo() function is define at the beginning of shell script. As you refer the command line args/option for shell script, same way you can refer the parameter for function. To pass the parameter to function we write it statement as follows in shell script:
demo -f foo bar
This statement passes three parameter to function demo -f, foo and bar. All of these parameters are stored to $1, $2, and $3 variable of function demo(). To clear your idea lets see one more example of parameter passing to function.

$ vi pass1
function cal()
[
n1=$1
op=$2
n2=$3
ans=0
if [ $# -eq 3 ]; then
  ans=$(( $n1 $op $n2 ))
  echo "$n1 $op $n2 = $ans"
  return $ans
else
  echo "Function cal requires atleast three args"
fi
 return
]
cal 5 + 10
cal 10 - 2
cal 10 / 2
echo $?

Run the above script as follows:
$ chmod +x pass1
$ ./pass1

5 + 10 = 15
10 - 2 = 8
10 / 2 = 5
5

Above script introduces some new concepts lets explore them step by step:

Command(s)/Statements
Explanation
function cal()
[
Begins the function definition for our cal() function
n1=$1
op=$2
n2=$3
ans=0
Stores the parameter passed to our function cal(). So if we called cal() as cal 5 + 10. Then store the values as follows:
n1=5
op=+
n2=10
and ans to zero value.
If [ $# -eq 3 ]; then
  ans=$(( $n1 $op $n2 ))
  echo "$n1 $op $n2 = $ans"
  return $ans
First see that sufficient parameter is passed or not. If sufficient parameter passed then do the calculation as per given operator on given two numbers. Then prints the calculation result using " echo $n1 $op $n2 = $ans" statement. return $ans statement is used to return the value of calculation. You can print this returned value using bashs built in variable $?
else
echo "Function cal requires atleast three args"
fi
return
]
If sufficent parameter not given then print the message "Function cal requires atleast three args" and terminate the function cal().
cal 5 + 10
cal 10 - 2
cal 10 / 2
Call the function cal to do different calculations.
echo $? Use to retrieve and print the value returned by cal(). Even you can store this value to variable by simply writing statement i=$?.